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Have HandleShellCommand return the stdout

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HandleShellCommand will now return the stdout as a string and
it also takes an additional flag indicating whether it should
wait before closing the shell and returning to the editor.
This commit is contained in:
Zachary Yedidia
2016-09-06 19:27:57 -04:00
parent 94465ef1ae
commit dce56a2b85
5 changed files with 27 additions and 14 deletions
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6
runtime/help/plugins.md
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@@ -73,8 +73,10 @@ as Go's GOOS variable, so `darwin`, `windows`, `linux`, `freebsd`...)
* `HandleCommand(cmd string)`: runs the given command
* `HandleShellCommand(shellCmd string, interactive bool)`: runs the given shell
command
* `HandleShellCommand(shellCmd string, interactive bool, waitToClose bool)`: runs the given shell
command. The `interactive` bool specifies whether the command should run in the background. The
`waitToClose` bool only applies if `interactive` is true and means that it should wait before
returning to the editor.
* `JobStart(cmd string, onStdout, onStderr, onExit string, userargs ...string)`:
Starts running the given shell command in the background. `onStdout` `onStderr` and `onExit`

2
runtime/help/tutorial.md
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@@ -80,7 +80,7 @@ You can do that by putting the following in `init.lua`:
function gorun()
local buf = CurView().Buf -- The current buffer
if buf:FileType() == "go" then
HandleShellCommand("go run " .. buf.Path, true) -- true means don't run it in the background
HandleShellCommand("go run " .. buf.Path, true, true) -- the first true means don't run it in the background
end
end